По теореме синусов:
[m]\frac{BC}{sin ∠A }=\frac{AC}{sin ∠B}[/m]
[m]sin 105° =sin (45 ° +60 °)=sin45° \cdot cos60 ° +cos 45°\cdot sin60 ° =\frac{\sqrt{2}}{2}\cdot \frac{1+\sqrt{3}}{2}[/m]
[m]AC=\frac{BC \cdot sin ∠B }{sin ∠A }=\frac{5\sqrt{2}\cdot \frac{\sqrt{2}}{2}\cdot \frac{1+\sqrt{3}}{2}}{\frac{1}{2}}=5(1+\sqrt{3}) ≈5(1+1,73)= 13,65[/m]