Задача 60060 yy' = x, y(0) = 1, (y(3))^2 = ? ...

60b60391a1c50e1d3043922e

01.06.2021 18:16:45

yy' = x, y(0) = 1, (y(3))^2 = ?

5f3ea7e3faf909182968ddd9

01.06.2021 18:29:34

★

y`=dy/dx

y*dy=xdx

∫ y*dy= ∫ xdx

y^2/2=x^2/2 + C_(1)

[b]y^2=x^2+C[/b]

y(0)=1

1=0^2+C

C=1


(y(3))^2=3^2+1

(y(3))^2=9+1

Ответ: 10