AO=(2/5)*3x=(6/5)x=1,2x
OD=(3/5)*3x=(9/5)x=1/8x
Проводим ВК || CD
тогда
vector{BK}=vector{CD}=vector{b}
По правилу треугольника
vector{AB}+vector{BK}=vector{AK}
-vector{a}+vector{b}=vector{AK}
vector{AO}=0,6*vector{AK}=-0,6*vector{a}+0,6vector{b}
vector{AD}=1,5vector {AK}=-1,5vector{a}+1,5vector{b}
vector {OD}=vector {AD}-vector{AO}=-0,9vector{a}+0,9vector{b}
1)
vector{CD}+vector{DO}=vector{CO}
vector{CO}=vector{b}+0,9vector{a}-0,9vector{b}=[b]0,9[/b]vector{a}+[b]0,1[/b]vector{b}